Integrand size = 27, antiderivative size = 45 \[ \int \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \, dx=\frac {(c+d x)^{1+n} \operatorname {Hypergeometric2F1}\left (-m,1+n,2+n,\frac {b (c+d x)}{b c-a d}\right )}{d (1+n)} \]
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Time = 0.01 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.074, Rules used = {192, 71} \[ \int \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \, dx=\frac {(c+d x)^{n+1} \operatorname {Hypergeometric2F1}\left (-m,n+1,n+2,\frac {b (c+d x)}{b c-a d}\right )}{d (n+1)} \]
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Rule 71
Rule 192
Rubi steps \begin{align*} \text {integral}& = \int (c+d x)^n \left (-\frac {a d}{b c-a d}-\frac {b d x}{b c-a d}\right )^m \, dx \\ & = \frac {(c+d x)^{1+n} \, _2F_1\left (-m,1+n;2+n;\frac {b (c+d x)}{b c-a d}\right )}{d (1+n)} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.96 \[ \int \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \, dx=\frac {(a+b x) \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \left (\frac {b (c+d x)}{b c-a d}\right )^{-n} \operatorname {Hypergeometric2F1}\left (1+m,-n,2+m,\frac {d (a+b x)}{-b c+a d}\right )}{b (1+m)} \]
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\[\int \left (\frac {d \left (b x +a \right )}{a d -b c}\right )^{m} \left (d x +c \right )^{n}d x\]
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\[ \int \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \, dx=\int { {\left (d x + c\right )}^{n} \left (-\frac {{\left (b x + a\right )} d}{b c - a d}\right )^{m} \,d x } \]
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Exception generated. \[ \int \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \, dx=\text {Exception raised: HeuristicGCDFailed} \]
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\[ \int \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \, dx=\int { {\left (d x + c\right )}^{n} \left (-\frac {{\left (b x + a\right )} d}{b c - a d}\right )^{m} \,d x } \]
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\[ \int \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \, dx=\int { {\left (d x + c\right )}^{n} \left (-\frac {{\left (b x + a\right )} d}{b c - a d}\right )^{m} \,d x } \]
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Timed out. \[ \int \left (\frac {d (a+b x)}{-b c+a d}\right )^m (c+d x)^n \, dx=\int {\left (c+d\,x\right )}^n\,{\left (\frac {d\,\left (a+b\,x\right )}{a\,d-b\,c}\right )}^m \,d x \]
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